Atlasfreeman Posted June 25 Share Posted June 25 (edited) Doing a portfolio website for my self. Each project has a "cover_img" inside a block first thing on page. I want to make an array on front page that find template basic page and give me the photo and the title for each page. the tilte works but not the photo.. I simply do not know how to say that the "cover_img" is inside the $block inside $page. Can some one help me? Here is the code: <section class="rpb-archive" <?= $block->styles() ?> <?= alfred($block) ?>> <?php $link = $pages->find("template=basic-page, limit=9, sort=parent.sort, sort=sort"); foreach ($link as $content) { echo "<div class='content_link'>"; echo "<div class='content_link_wrap'>"; $image = $content->$block->cover_img; // Access the block property dynamically if ($image) { $cover_image = $image->size(0, 2000); echo "<a href='{$content->url}'><img src='{$cover_image->url}' alt='{$cover_image->description}'></a>"; } echo "<a class='title' href='{$content->url}'><h2 class='content_text'>{$content->title}</h2></a>"; echo "</div>"; echo "</div>"; } ?> </section> Edited October 14 by Atlasfreeman Link to comment Share on other sites More sharing options...
BrendonKoz Posted June 25 Share Posted June 25 Because you're referencing the image dynamically, it's hard to say what it should be here. What you can do though is, if you have the Tracy Debugger module installed, do a few db() calls on $content to try to identify what is actually contained in the value you're retrieving within $link. Try $content, $block, $content->$block, etc. I suspect that you are just not referencing the correct object name, but since you're calling things dynamically, you'll need to do some debugging of your own to figure out what's going on. 1 Link to comment Share on other sites More sharing options...
wbmnfktr Posted June 27 Share Posted June 27 Could it be that you acutally use a multi-image field aka an image field that allows multiple images? If so that image part needs to be in a foreach() or you need to use $image->first() and go from there. // probably easier to use first() here as you only want to show one picture $image = $content->$block->cover_img; // Access the block property dynamically if ($image) { $cover_image = $image->first()->size(0, 2000); echo "<a href='{$content->url}'><img src='{$cover_image->first()->url}' alt='{$cover_image->first()->description}'></a>"; } 1 Link to comment Share on other sites More sharing options...
Atlasfreeman Posted August 27 Author Share Posted August 27 In the this was the code i used: <?php echo "<div class='archive_wrapper'>"; $link = $pages->find("template=basic-page|basic-page-book, sort=parent.sort, sort=sort"); foreach ($link as $content){ echo "<div class='content_link'>"; echo "<div class='content_link_wrap'>"; $block_img = $content->cover_img; if ($block_img) { echo "<a href='{$content->url}'><img class='maxheight' src='{$block_img->url}' alt='{$block_img->description}'></a>"; } echo "<a class='title' href='{$content->url}'><h2 class='content_text'>{$content->title}</h2></a>"; echo "</div>"; echo "</div>"; } echo "</div>"; ?> Link to comment Share on other sites More sharing options...
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