Rendering partial content?

[PaulAik]

Wondering if I can render out partial content via the API, and pass through either the current page, or a set of variables.

E.g. instead of this:

$content = "<h1>This is the content</h1>";

I'd love to do this:

$content = $something -> render('/site/templates/views/partials/partialcontent.html.php', $page);

I've seen in the API docs the ability to render pages as partials, but I think this is a bit different (e.g. partialcontent isn't a page itself).

[PaulAik]

Possibly answering my own question here... will wireRenderFile do the trick?

https://processwire.com/blog/posts/processwire-2.5.2/#new-wirerenderfile-and-wireincludefile-functions

[LostKobrakai]

That's exactly what you want to have. wireRenderFile() and $page->render($options) should be enought to fit the needs here. 

[qtguru]

Seriously guys why don't i know about this ? now this will make things a lot more better

[adrianmak]

That's exactly what you want to have. wireRenderFile() and $page->render($options) should be enought t

The example code shown in the blog post,

$photo = $page->photos->getRandom();
$sidebar = wireRenderFile("inc/fancy_sidebar", array('photo' => $photo));

the wireRenderFile() function will auto append .php file extension to fancy_sidebar ?

[LostKobrakai]

Yeah, it does append .php if no extentions is given.

[adrianmak]

I tried testing the wideRenderFile but no success.

a template file

$temp = wireRenderFile("test", array('content' => $page->body)); 
echo $temp;

test.php

<?php 
   
    $content .= "AAAAAAAAAAAAAA";

There is not outputted content of $temp.

[LostKobrakai]

wireRenderFile does return the output of the included file. So everything you echo in test.php will be returned to $temp as string. The passed variables are only made available as copies, but they do not automatically make the function return anything.