PHP Menu - Syntax error

[Timbo]

Hey there,

I'm on my first website using ProcessWire and I'm not a PHP-Crack

So my Problem is: I want to make a horizontal nav menu, where the <li> element has the class="active" for the current page.

so here my PHP code:

         <?php
        $root = $pages->get("/");
        $children = $root->children();
        foreach($children as $child)
        {
            if($child === $page)
            {
syntaxerror---> echo "<li class="active"><a href='{$child->url}'>{$child->title}</a></li>";
            }
            else
            {
                echo "<li><a href='{$child->url}'>{$child->title}</a></li>";
            }
        }
        ?>
 

anyone got an Idea?

Thanks

[interrobang]

Your quotes around "active" are the problem, try this:

<?php

$root = $pages->get("/");

$children = $root->children();

foreach ($children as $child) {

if ($child === $page) {

// I changed "active" to 'active' so your quotes dont break the echo.

echo "<li class='active'><a href='{$child->url}'>{$child->title}</a></li>";

} else {

echo "<li><a href='{$child->url}'>{$child->title}</a></li>";

}

}

?>

[Luis]

Change your " in class declaration into '

Edit:

Hmpf too Late

[Timbo]

Hahaha damn I knew that was such a dumb noob-error Tanks, next time i will know it