if(!isset($page )) ?

[martind]

why does an if statement like this not work as expected...

if($input->urlSegment2 OR !isset($page))

... i try to execute different php-code in my head.inc for direct page calls (if this ist the right term, www.domain.tld/entry/page-name/ where template "entry" uses the $page array) and such that make use of urlSegments with infos for $pages->find in a different template. What i`m doing wrong?

[diogo]

This won't work because the $page variable will always be set. If you want to test for the existence of segments, this will be enough if($input->urlSegment1)

[martind]

hm, but how can I make a distinction like this?

if(isset($page)) {
$parent_page = $page->parent;
}else{
$parent_page = $input->urlSegment2;
}

[arjen]

I think you can check against $page->id instead of $page.

[martind]

I think you can check against $page->id instead of $page.

ah, of course. Thank you arjen, this works.

[martind]

I think you can check against $page->id instead of $page.

mhm, no, works only for a if true condition. but

if(!$page instanceof NullPage)

did it.

[arjen]

That should work. To minimize the code you can also try to turnaround the statement using an ifnot (!).

if (!$page->id) {
  // do stuff
}