Only show pages in use via PageField

[a-ok]

Hi all.

I'm using a simple parent/children page setup to act like categories (Categories > category 1, category 2, category 3 etc).

When adding a new page, using the PageField, the user can multi-select which 'categories' this page relates to. Simple. On the front end I am looping through the categories:

<?php $categories = $pages->find('parent=/categories/, sort=name'); ?>
<?php foreach ($categories as $category) : ?>
<li><a href="#" data-name="<?php echo $category->name; ?>"><?php echo $category->title; ?></a></li>
<?php endforeach; ?>

This is then going to act as a filter... however... I'm wondering if it's possible to only show the categories that are currently in use... rather than showing them all? What do you think?

[Sergio]

You can have something like this, considering your page field is called "categories".

Not tested! 

<?php $categories = $pages->find('parent=/categories/, sort=name'); ?>
<?php 
	foreach ($categories as $category) : 
	if ($pages->count("categories=$category")) > 0 :
?>
<li><a href="#" data-name="<?php echo $category->name; ?>"><?php echo $category->title; ?></a></li>
<?php endif; endforeach; ?>

 

[LostKobrakai]

See Ryan's answer here: 

 

[a-ok]

2 hours ago, Sérgio said:

You can have something like this, considering your page field is called "categories".

Not tested! 

<?php $categories = $pages->find('parent=/categories/, sort=name'); ?>
<?php 
	foreach ($categories as $category) : 
	if ($pages->count("categories=$category")) > 0 :
?>
<li><a href="#" data-name="<?php echo $category->name; ?>"><?php echo $category->title; ?></a></li>
<?php endif; endforeach; ?>

 

This was perfect, thanks.