Pagination create different markup for active link

[hberg539]

Hello,

i'm currently using this setup for my pagination:

				$results = $baustelle->children("limit=2");
				$pagination = $results->renderPager(array(
					'nextItemLabel' => "Next",
					'previousItemLabel' => "Prev",
					'listMarkup' => "<ul class='pagination mg-b-0'>{out}</ul>",
					'itemMarkup' => "<li class='page-item {class}'>{out}</li>",
					'linkMarkup' => "<a class='page-link' href='{url}'>{out}</a>",
					'currentItemClass' => "active"
				));
				echo $pagination;

PW generates the following output (see the html-comment <!-- -->):

    <li class="active MarkupPagerNavFirst MarkupPagerNavFirstNum">
        <a href="/test/"> <!-- different markup as in linkMarkup specified -->
            <span>
                1
            </span>
        </a>
    </li>
    <li class="MarkupPagerNavLastNum">
        <a class="page-link" href="/test/page2">
            2
        </a>
    </li>
    <li class="MarkupPagerNavNext MarkupPagerNavLast">
        <a class="page-link" href="/test/page2">
            Next
        </a>
    </li>

</ul>

Is this expected behaivor? How can i add the class "page-link" in the a-tag in the current active page?

Thanks!

Best regards,

Kevin

Edited April 5, 2018 by hberg539

[Sergio]

Hi Kevin! Welcome to the forums.

Add the "currentLinkMarkup" to your array, like this:

$results = $baustelle->children("limit=2");
$pagination = $results->renderPager(array(
  'nextItemLabel' => "Next",
  'previousItemLabel' => "Prev",
  'listMarkup' => "<ul class='pagination mg-b-0'>{out}</ul>",
  'itemMarkup' => "<li class='page-item {class}'>{out}</li>",
  'linkMarkup' => "<a class='page-link' href='{url}'>{out}</a>",
  'currentLinkMarkup' => "{out}",
  'currentItemClass' => "active"
));
echo $pagination;

 

[hberg539]

Thanks, works like a charm.

(The "currentLinkMarkup" Parameter is missing in the documentation: https://processwire.com/api/modules/markup-pager-nav/)