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*To*: tesla@xxxxxxxxxx*Subject*: capacitance of transmissionline (magnifier)*From*: "Tesla list" <tesla@xxxxxxxxxx>Fritz <teslalist@xxxxxxxxxxxxxxxxxxxxxxx>, ")"@pupman.com*Date*: Mon, 21 Mar 2005 18:47:59 -0700*Delivered-to*: testla@pupman.com*Delivered-to*: tesla@pupman.com*Old-return-path*: <teslalist@twfpowerelectronics.com>*Resent-date*: Mon, 21 Mar 2005 18:49:26 -0700 (MST)*Resent-from*: tesla@xxxxxxxxxx*Resent-message-id*: <YydoxB.A.mtG.bm3PCB@poodle>*Resent-sender*: tesla-request@xxxxxxxxxx

Original poster: =?iso-8859-1?Q?"Dieter_Böckeler"?= <Dieter.Boeckeler@xxxxxxxxxxx>

I´ve calculated the capacitance of the transmissionline conductors in magnifiers

and I found a high value for the capacity.

I used the formula: C=2*Pi*E0*Er*L/ln(2*a/r)

E0=0,8854*10^-12 constant

Er for air=1

L=length of conductor (in metres)

a=distance to earth (in metres)

r=radius of conductor (in metres)

With the dimensions:

L=5 metres

a=1 metres

r=0,014 metres

I´ve calculated a value of 56pF.another formula gives a 10pf higher value.

rather high I guess.(is this formula correct?)

I calculated the surface of the conductor,and I got the same surface than a 14,7" ball,

but more capacitance.

On some magnifier sites is written about the fine tuning with transmissionline capacity.

But with such high values you can´t say fine tuning.

Another question is about coupling coefficient and effective coupling:

Keff=Kd*sqrt(L2/L2+L3)

and Kd=M/sqrt(L1xL2)

I read somwhere that the problem with fast quenching only occurs from the effective k.

Is this true?

best regards

alex

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