Related projects

[Jon E]

Hi,

I have created a page field type called related_projects.

I want to output this on a template. I need to limit it to 2 and to:

- Find the project name

- The first image from a field named images

Can anyone help me please?

I've really had a good look but totally stuck, especially with the image...

Thanks so much.

Jon

[Macrura]

you mean like this?

<?php

$relatedProjects = $pages->find("template=project,limit=2");

foreach($relatedProjects as $rp) {
	echo "<h2>{$rp->title}</h2>";
	echo '<img src="' . $rp->images->first()->url . '" alt='' />';
}

[Jon E]

Hi,

Not sure that will work, I need to find the pages selected in my related_projects field...

Thanks though...

[Macrura]

$relatedProjects = $page->related_projects->find("limit=2");

[Jon E]

Thanks looks like that would work but....

Parse Error: syntax error, unexpected '' . $rp->images->first()->url ' (T_CONSTANT_ENCAPSED_STRING), expecting ',' or ';' (line 39 of 

[Jon E]

Hi,

Got it working with the below, thanks so much.

Does anyone know how I can only show the #related_projects div if I have options selected?

Seems to be showing on all pages currently.

Sorry to be annoying and thanks so much.

Jon

<?php if($page->related_projects):?>
<div id="related_projects">
<h2>You might like...</h2>

<?php

$relatedProjects = $page->related_projects->find("limit=2");

   

foreach($relatedProjects as $rp) {
    echo "<li><a href='{$rp->url}'><img src='{$rp->images->first()->url}'>";
    echo "<h3>{$rp->title}</h3></a></li>";
}

?>

</div>
<?php endif; ?>

[diogo]

if($page->related_projects->count > 0)

[Jon E]

Thank you so much for all your help.